C(q)=810+3q+0.002q^2

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Solution for C(q)=810+3q+0.002q^2 equation: 



(C)=810+3C+0.002C^2

We move all terms to the left:

(C)-(810+3C+0.002C^2)=0

We get rid of parentheses

-0.002C^2-3C+C-810=0

We add all the numbers together, and all the variables

-0.002C^2-2C-810=0

a = -0.002; b = -2; c = -810;
Δ = b2-4ac
Δ = -22-4·(-0.002)·(-810)
Δ = -2.48
Delta is less than zero, so there is no solution for the equation

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